Physics question (please give step by step instructions)?
A golfer hits a golf ball at an angle of 25.0 degrees to the ground. if the golf ball covers a hoirzontal distance of 301.5m, whtat is teh ball’s maxmum height?
(hint: at the top of its flight, the ball’s vertical velocity component will be zero)
I would greatly appreciate someone showing how to do this problem step by step. I was absent so i would really like to learn how to solve it rather than get get an answer.
Thank you
Use the range eqn to determine the initial velocity:
range= 301.5m = ((Vo)²•sin(2Θ))/g = Vo² • sin50º / 9.8m/s²
Therefore Vo = 62.1 m/s
Use the max height eqn:
max. height=(Vo • sinΘ)² / (2g) = ( (62.1m/s)² • sin25º)² / (2•9.8m/s²) = 35.1 m
I suspect you missed the presentation of these two equations which often provide a quick solution.